NIMCET 2012 — Mathematics PYQ
NIMCET | Mathematics | 2012If (4,−3) and (−9,7) are the two vertices of a triangle and (1,4) is its centroid, then area of triangle is:
Choose the correct answer:
- A.
2138
- B.
2319
- C.
2183
2183
Explanation
Solution
-
Find the third vertex (x3,y3):
Given vertices are A(4,−3) and B(−9,7). Centroid G is (1,4).
Using Centroid Formula: G=(3x1+x2+x3,3y1+y2+y3)
For x-coordinate:
1=34+(−9)+x3⟹3=−5+x3⟹x3=8
For y-coordinate:
4=3−3+7+y3⟹12=4+y3⟹y3=8
Third vertex C is (8,8).
-
Calculate the Area of Triangle:
Using the formula: Area=21∣x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣
Substitute A(4,−3), B(−9,7), and C(8,8):
Area=21∣4(7−8)+(−9)(8−(−3))+8(−3−7)∣Area=21∣4(−1)−9(11)+8(−10)∣Area=21∣−4−99−80∣Area=21∣−183∣Area=2183
Correct Option: (c)
Explanation
Solution
-
Find the third vertex (x3,y3):
Given vertices are A(4,−3) and B(−9,7). Centroid G is (1,4).
Using Centroid Formula: G=(3x1+x2+x3,3y1+y2+y3)
For x-coordinate:
1=34+(−9)+x3⟹3=−5+x3⟹x3=8
For y-coordinate:
4=3−3+7+y3⟹12=4+y3⟹y3=8
Third vertex C is (8,8).
-
Calculate the Area of Triangle:
Using the formula: Area=21∣x1(y2−y3)+x2(y3−y1)+x3(y1−y2)∣
Substitute A(4,−3), B(−9,7), and C(8,8):
Area=21∣4(7−8)+(−9)(8−(−3))+8(−3−7)∣Area=21∣4(−1)−9(11)+8(−10)∣Area=21∣−4−99−80∣Area=21∣−183∣Area=2183
Correct Option: (c)

