1. Comparing I1 and I2 (Interval 0 < x < 1):
In the interval x∈(0,1), higher powers of x result in smaller values.
Since the base (2) is greater than 1, the inequality remains the same when used as an exponent:
Integrating both sides from 0 to 1:
\int_{0}^{1} 2^{x^2} \, dx > \int_{0}^{1} 2^{x^3} \, dx
Therefore, I_1 > I_2. (This makes options (a) and (b) incorrect).
2. Comparing I3 and I4 (Interval 1 < x < 2):
In the interval x∈(1,2), higher powers of x result in larger values.
Again, since the base (2) is greater than 1:
Integrating both sides from 1 to 2:
\int_{1}^{2} 2^{x^3} \, dx > \int_{1}^{2} 2^{x^2} \, dx
Therefore, I_4 > I_3.
Conclusion:
By comparing the growth of the functions 2x2 and 2x3 in the specific intervals, we find that I4 is definitely greater than I3.
Correct Option: (d)