NIMCET 2011 — Reasoning PYQ

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Question

NIMCET 2011 — Reasoning PYQ

NIMCET | Reasoning | 2011

Directions : Q. Mrs. Thomes received a large order for stitching school uniforms from Mayflower school and Littleflower school. She has two cutters who will cut the fabric, five tailors who will do the stitching and two assistants to stitch the button and button holes. Each of these nine persons will work for exactly 10 hours a day. Each of the Mayflower uniforms requires 20 min. for cutting the fabric, one hour for stitching, and 15 min. for stitching buttons and button holes, whereas the Littleflower uniform requires 30 min., 1 hour and 30 min. respectively for these activities.

On a particular day, Mrs. Thomes decided to complete 20 Littleflower uniforms. How many Mayflower uniforms can she complete on that day ?

Choose the correct answer:

Explanation

Solution

Total Available Time (per day):
- $\text{Cutting (2 Cutters)} = 2 \times 10 \times 60 = 1200 \text{ min}$
- $\text{Stitching (5 Tailors)} = 5 \times 10 \times 60 = 3000 \text{ min}$
- $\text{Buttons (2 Assistants)} = 2 \times 10 \times 60 = 1200 \text{ min}$
Time consumed by 20 Littleflower Uniforms:
- $\text{Cutting} = 20 \times 30 = 600 \text{ min}$
- $\text{Stitching} = 20 \times 60 = 1200 \text{ min}$
- $\text{Buttons} = 20 \times 30 = 600 \text{ min}$
Remaining Time for Mayflower Uniforms:
- $\text{Cutting Left} = 1200 - 600 = 600 \text{ min}$
- $\text{Stitching Left} = 3000 - 1200 = 1800 \text{ min}$
- $\text{Buttons Left} = 1200 - 600 = 600 \text{ min}$
Potential Mayflower Uniforms ( $n$ ):
- $\text{From Cutting} = \frac{600}{20} = 30$
- $\text{From Stitching} = \frac{1800}{60} = 30$
- $\text{From Buttons} = \frac{600}{15} = 40$

Conclusion:

The maximum number of Mayflower uniforms is limited by the minimum capacity of the three departments.

\text{Max Mayflower Uniforms} = \min(30, 30, 40) = 30

Correct Option: (a) 30