Explanation
1. Set up the determinant D:
D=312amp;7amp;2amp;3amp;1amp;1amp;4
2. Expand the determinant along the first row:
D=3(2×4−3×1)−7(1×4−2×1)+1(1×3−2×2)
3. Analyze the result:
Since D=0, the system either has infinitely many solutions or no solution. We must now check the determinants D1,D2, or D3 (Cramer's Rule).
4. Calculate D1 (replace first column with constants 2, 3, 13):
D1=2313amp;7amp;2amp;3amp;1amp;1amp;4
D1=2(8−3)−7(12−13)+1(9−26)
Similarly, checking D2 and D3:
D2=312amp;2amp;3amp;13amp;1amp;1amp;4=3(12−13)−2(4−2)+1(13−6)=−3−4+7=0
D3=312amp;7amp;2amp;3amp;2amp;3amp;13=3(26−9)−7(13−6)+2(3−4)=51−49−2=0
Conclusion:
Since D=0 and D1=D2=D3=0, the system of equations has infinitely many solutions.
The correct option is (a).