NIMCET 2010 — Mathematics PYQ
NIMCET | Mathematics | 2010Derivative of sinx2 with respect to 2x2 is:
Choose the correct answer:
- A.
21cos2x
- B.
cos(2x2)
21cosx2
Explanation
1. Let u and v be the functions:
u=sinx2
v=2x2
2. Differentiate u with respect to x:
Using the chain rule:
dxdu=cos(x2)⋅dxd(x2)
dxdu=2xcosx2
3. Differentiate v with respect to x:
dxdv=dxd(2x2)
dxdv=4x
4. Find dvdu:
dvdu=4x2xcosx2
dvdu=42cosx2
dvdu=21cosx2
Correct Option:
(d) 21cosx2
Explanation
1. Let u and v be the functions:
u=sinx2
v=2x2
2. Differentiate u with respect to x:
Using the chain rule:
dxdu=cos(x2)⋅dxd(x2)
dxdu=2xcosx2
3. Differentiate v with respect to x:
dxdv=dxd(2x2)
dxdv=4x
4. Find dvdu:
dvdu=4x2xcosx2
dvdu=42cosx2
dvdu=21cosx2
Correct Option:
(d) 21cosx2
