NIMCET 2010 — Mathematics PYQ
NIMCET | Mathematics | 2010If and , then the value of is:

If a=p,b=q,c=r and paaamp;bamp;qamp;bamp;camp;camp;r=0, then the value of p−ap+q−bq+r−cr is:
0
1
-1
2
(Correct Answer)2
1. Apply Row Operations:
To simplify the determinant, we can use row operations. Let's perform:
R2→R2−R1
R3→R3−R1
The determinant becomes:
2. Expand the Determinant:
Expanding along the first row (R1):
3. Adjust the Signs:
Since we need terms like p−a, let's replace (a−p) with −(p−a):
4. Divide by (p−a)(q−b)(r−c):
To reach the required form, divide the entire equation by (p−a)(q−b)(r−c):
5. Convert b and c terms to q and r:
We need the numerators to be q and r. We can rewrite the fractions:
q−bb=q−bb−q+q=q−b−(q−b)+q=−1+q−bq
r−cc=r−cc−r+r=r−c−(r−c)+r=−1+r−cr
Substitute these back into the equation:
Correct Option: (d) 2
1. Apply Row Operations:
To simplify the determinant, we can use row operations. Let's perform:
R2→R2−R1
R3→R3−R1
The determinant becomes:
2. Expand the Determinant:
Expanding along the first row (R1):
3. Adjust the Signs:
Since we need terms like p−a, let's replace (a−p) with −(p−a):
4. Divide by (p−a)(q−b)(r−c):
To reach the required form, divide the entire equation by (p−a)(q−b)(r−c):
5. Convert b and c terms to q and r:
We need the numerators to be q and r. We can rewrite the fractions:
q−bb=q−bb−q+q=q−b−(q−b)+q=−1+q−bq
r−cc=r−cc−r+r=r−c−(r−c)+r=−1+r−cr
Substitute these back into the equation:
Correct Option: (d) 2