NIMCET 2010 — Mathematics PYQ
NIMCET | Mathematics | 2010In a triangle , is circumradius and . The triangle is:

In a triangle ABC, R is circumradius and 8R2=a2+b2+c2. The triangle ABC is:
Acute angled
Obtuse angled
Right angled
(Correct Answer)None of these
Right angled
1. Recall the Sine Rule:
In any triangle ABC, the relationship between the sides and the circumradius R is given by:
From this, we can express the sides in terms of R and the angles:
a=2RsinA
b=2RsinB
c=2RsinC
2. Substitute into the Given Equation:
The problem states that:
Substituting the expressions for a,b, and c:
3. Simplify the Equation:
Divide both sides by 4R2 (assuming R=0):
4. Use Trigonometric Identities:
Using the identity sin2θ=21−cos2θ:
Using the sum-to-product formula cosX+cosY=2cos2X+Ycos2X−Y:
Since A+B+C=π, then cos(A+B)=cos(π−C)=−cosC.
Substitute C=π−(A+B) back into the bracket:
5. Conclusion:
For the product to be zero, at least one factor must be zero:
This implies that one of the angles (A,B, or C) must be 90∘ (or 2π).
Therefore, the triangle ABC is Right angled.
Correct Option: (c)
1. Recall the Sine Rule:
In any triangle ABC, the relationship between the sides and the circumradius R is given by:
From this, we can express the sides in terms of R and the angles:
a=2RsinA
b=2RsinB
c=2RsinC
2. Substitute into the Given Equation:
The problem states that:
Substituting the expressions for a,b, and c:
3. Simplify the Equation:
Divide both sides by 4R2 (assuming R=0):
4. Use Trigonometric Identities:
Using the identity sin2θ=21−cos2θ:
Using the sum-to-product formula cosX+cosY=2cos2X+Ycos2X−Y:
Since A+B+C=π, then cos(A+B)=cos(π−C)=−cosC.
Substitute C=π−(A+B) back into the bracket:
5. Conclusion:
For the product to be zero, at least one factor must be zero:
This implies that one of the angles (A,B, or C) must be 90∘ (or 2π).
Therefore, the triangle ABC is Right angled.
Correct Option: (c)