NIMCET 2010 — Reasoning PYQ

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Question

NIMCET 2010 — Reasoning PYQ

NIMCET | Reasoning | 2010

Directions: Questions : In each of the following three questions, four numbers are given. Out of these, three are alike in a certain way but the rest one is different. Choose the one which is different from the rest three .

Choose the correct answer:

Explanation

Solution:

The pattern is based on the relationship between the digits of each number. Specifically, the product of the first and last digits equals the middle two digits.

(a) $2384 \implies 2 \times 4 = 08 \neq 38$ (Does not follow)
(b) $3629 \implies 3 \times 9 = 27 \neq 62$ (Does not follow)
(c) $3756 \implies 3 \times 6 = 18 \neq 75$ (Does not follow)

Alternative Logic (Sum of Digits):

(a) $2+3+8+4 = 17$
(b) $3+6+2+9 = 20$
(c) $3+7+5+6 = 21$
(d) $4+2+9+8 = 23$

Correct Logic (Digit Addition/Relationship):

In many such competitive exams, the pattern for this specific set is:

Option (b) is the odd one because in all others, the sum of the digits is an odd number, whereas in (b), the sum is even ( $3+6+2+9 = 20$ ).