NIMCET 2010 — Reasoning PYQ

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Question

NIMCET 2010 — Reasoning PYQ

NIMCET | Reasoning | 2010

Directions : Questions : 220 guests are to be trans- ported from A to B. Any number of buses of the following passenger carrying capacities are available.
Type P : 60, Type Q : 50, Type R : 40, Type S : 30
The cost per trip for a bus of each of these types is given as follows :
Type P : Rs 200, Type Q : Rs 140, Type R : Rs 125,
Type S : Rs 95
No buses can be overloaded and prefer no vacant seats in each trips.

The second cheapest trip arrangement would involve

Choose the correct answer:

Explanation

1. Bus Specifications:

| :--- | :--- | :--- | :--- |

| P | 60 | 200 | 3.33 |

| Q | 50 | 140 | 2.80 |

| R | 40 | 125 | 3.125 |

| S | 30 | 95 | 3.16 |

2. Possible Combinations for 220 seats:

Combination A (3Q + 1R + 1S):
- Capacity: $(3 \times 50) + 40 + 30 = 220$
- Cost: $(3 \times 140) + 125 + 95 = 420 + 220 = Rs\ 640$ (Cheapest)
Combination B (2Q + 3R):
- Capacity: $(2 \times 50) + (3 \times 40) = 100 + 120 = 220$
- Cost: $(2 \times 140) + (3 \times 125) = 280 + 375 = Rs\ 655$
Combination C (1Q + 3R + 1S + ?): (Not possible to hit exactly 220 easily here)
- Let's try 4R + 2S:
- Capacity: $(4 \times 40) + (2 \times 30) = 160 + 60 = 220$
- Cost: $(4 \times 125) + (2 \times 95) = 500 + 190 = Rs\ 690$
Combination D (2P + 2Q):
- Capacity: $(2 \times 60) + (2 \times 50) = 120 + 100 = 220$
- Cost: $(2 \times 200) + (2 \times 140) = 400 + 280 = Rs\ 680$
Combination E (1P + 2Q + 1R + 1S):
- Capacity: $60 + (2 \times 50) + 40 + 30 = 60 + 100 + 40 + 30 = 230$ (Not valid, vacant seats)

3. Comparison of Valid Costs:

Rs 640 (3Q, 1R, 1S)
Rs 655 (2Q, 3R)
Rs 680 (2P, 2Q)
Rs 690 (4R, 2S)

Conclusion:

The cheapest trip is Rs 640, and the second cheapest arrangement costs Rs 655.

Correct Option: (d) Rs 655