A CPU has a bit address for memory addressing. If the memory has a total capacity of KB, what is the word length of the memory?

bytes Explanation: Solution The correct answer is: (b) 4 bytes Step-by-Step Calculation 1. Calculate the number of addressable locations: The number of locations (words) is determined by the number of address bits ( ): Given : Since K, we can write this as: 2. Identify the total memory capacity: Given Total Capacity = KB. 3. Calculate the word length: The total capacity is the product of the number of locations and the word length (bits/bytes per location).

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NIMCET 2010 — Computer PYQ

NIMCET | Computer | 2010

A CPU has a $12$ bit address for memory addressing. If the memory has a total capacity of $16$ KB, what is the word length of the memory?

Choose the correct answer:

Explanation

Solution

The correct answer is: (b) 4 bytes

Step-by-Step Calculation

1. Calculate the number of addressable locations:

The number of locations (words) is determined by the number of address bits ( $n$ ):

\text{Number of locations} = 2^n

Given $n = 12$ :

\text{Number of locations} = 2^{12} = 4096 \text{ words}

Since $2^{10} = 1$ K, we can write this as:

2^{12} = 2^2 \times 2^{10} = 4 \text{ K words}

2. Identify the total memory capacity:

Given Total Capacity = $16$ KB.

3. Calculate the word length:

The total capacity is the product of the number of locations and the word length (bits/bytes per location).

\text{Total Capacity} = \text{Number of locations} \times \text{Word length}

16 \text{ KB} = 4 \text{ K} \times \text{Word length}

\text{Word length} = \frac{16 \text{ KB}}{4 \text{ K}}

\text{Word length} = 4 \text{ bytes}