NIMCET 2013 — Reasoning PYQ

To find the inconsistency, we must refer to the rules established in Que. $65$:

• Rule (i): All $G$ are $H$.

• Rule (iv): All $N$ are $M$.

• Rule (v): No $M$ is $G$ ($M\cap G=\varnothing$).

Evaluating the Options:

• Option $1$: "Some $H$'s are $G$'s"

  • Since "All $G$ are $H$", if there is at least one $G$, then some $H$ must be $G$. This is consistent.

• Option $4$: "No $N$'s are $G$'s"

  • We know "All $N$ are $M$" and "No $M$ is $G$".

  • Therefore, since $N$ is a subset of $M$, and $M$ has no overlap with $G$, it is logically certain that $N$ cannot overlap with $G$. This is consistent.

• Evaluating Potential Inconsistency:

  • If the question implies that $H$ and $M$ are mutually exclusive (which is often hinted in these specific puzzles based on the "No $M$ is $G$" and "All $G$ are $H$" relationship), then saying "Some $H$ are $M$" or "All $H$ not in $G$ are $M$" might create a contradiction depending on whether $H$ can exist outside of $G$.

Correct Option - $2$ (Typically, in this specific logic set, $H$ is not required to be $M$ outside of the $G$ circle).