NIMCET 2013 Mathematics PYQ — Let be a triangle whose area is units with side lengths units and… | Mathem Solvex | Mathem Solvex
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NIMCET 2013 — Mathematics PYQ
NIMCET | Mathematics | 2013
Let ΔABC be a triangle whose area is 103 units with side lengths ∣AB∣=8 units and ∣AC∣=5 units. Find possible values of the angle A.
Choose the correct answer:
A.
60∘ or 120∘
(Correct Answer)
B.
45∘ or 135∘
C.
30∘ only
D.
90∘ only
Correct Answer:
60∘ or 120∘
Explanation
Solution
Step 1: Use the trigonometric formula for the area of a triangle
The area of a triangle when two sides and the included angle are given is:
Area=21×b×c×sin(A)
Given:
Area=103
c=∣AB∣=8
b=∣AC∣=5
Step 2: Substitute the values into the formula
103=21×5×8×sin(A)
103=20×sin(A)
Step 3: Solve for sin(A)
sin(A)=20103
sin(A)=23
Step 4: Determine the possible values for angle A
Since the sine function is positive in both the first and second quadrants, there are two possible angles for A within the range of a triangle (0^\circ < A < 180^\circ):
Case 1 (Acute):A=sin−1(23)=60∘
Case 2 (Obtuse):A=180∘−60∘=120∘
Both 60∘ and 120∘ are valid as they are less than 180∘.
Correct Option: 1. 60∘ or 120∘
Explanation
Solution
Step 1: Use the trigonometric formula for the area of a triangle
The area of a triangle when two sides and the included angle are given is:
Area=21×b×c×sin(A)
Given:
Area=103
c=∣AB∣=8
b=∣AC∣=5
Step 2: Substitute the values into the formula
103=21×5×8×sin(A)
103=20×sin(A)
Step 3: Solve for sin(A)
sin(A)=20103
sin(A)=23
Step 4: Determine the possible values for angle A
Since the sine function is positive in both the first and second quadrants, there are two possible angles for A within the range of a triangle (0^\circ < A < 180^\circ):
Case 1 (Acute):A=sin−1(23)=60∘
Case 2 (Obtuse):A=180∘−60∘=120∘
Both 60∘ and 120∘ are valid as they are less than 180∘.