NIMCET 2014 — Computer PYQ

Q: How do I solve NIMCET 2014 Computer questions?

Practice NIMCET 2014 Computer previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

Q: What is the difficulty level of NIMCET Computer questions?

NIMCET Computer questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Q: Are NIMCET previous year papers available for free?

Yes. Mathem Solvex provides free access to NIMCET previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

Question

NIMCET 2014 — Computer PYQ

NIMCET | Computer | 2014

The result of multiplication of the numbers $(10101)_2$ and $(11101)_2$ in hexadecimal form is:

Choose the correct answer:

Explanation

Solving

Step 1: Convert Binary to Decimal

$(10101)_2 = 1 \cdot 2^4 + 0 \cdot 2^3 + 1 \cdot 2^2 + 0 \cdot 2^1 + 1 \cdot 2^0 = 16 + 4 + 1 = 21_{10}$
$(11101)_2 = 1 \cdot 2^4 + 1 \cdot 2^3 + 1 \cdot 2^2 + 0 \cdot 2^1 + 1 \cdot 2^0 = 16 + 8 + 4 + 1 = 29_{10}$

Step 2: Multiply the Decimal values

21 \times 29 = 609_{10}

Step 3: Convert Decimal result to Hexadecimal

Divide $609$ by $16$ repeatedly:

$609 \div 16 = 38$ with remainder $1$ (Least Significant Digit)
$38 \div 16 = 2$ with remainder $6$
$2 \div 16 = 0$ with remainder $2$ (Most Significant Digit)

Reading the remainders from bottom to top: $(261)_{16}$

Correct Option: 3. $261$