All the roads of a city are either perpendicular or parallel to one another. The roads are all straight. Roads and are parallel to one another. Roads and are parallel to one another. Road is East of road . Road is West of road . Road is West of road . Road is South of road . Road is North of road . Road is North of road . Road is South of road . If is parallel to , is South of and North of , then which of the following two roads would be apart?

and Explanation: Solution Step 1: Identify the orientation of Road K series Since are parallel and involve East/West directions, they are Vertical (North-South) roads. Since are parallel and involve North/South directions, they are Horizontal (East-West) roads. Step 2: Map the Vertical positions (North to South) Let's establish the relative North-South positions of the horizontal roads based on the given conditions: From the prompt's specific condition: is South of . Distance: From the main text: is North of . Distance: From the prompt's specific condition: is North of . Distance: Step 3: Combine the sequence (North to South) Top: Road (Gap of ) Road (Gap of ) Road (Gap of ) Road Step 4: Verify the distances Distance between I and K: Distance between J and G: Distance between I and G: Distance between J an

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NIMCET 2014 — Reasoning PYQ

NIMCET | Reasoning | 2014

All the roads of a city are either perpendicular or parallel to one another. The roads are all straight. Roads $A, B, C, D$ and $E$ are parallel to one another. Roads $F, G, H, I, J, K, L$ and $M$ are parallel to one another.

Road $A$ is $1\text{ km}$ East of road $B$ .
Road $B$ is $1/2\text{ km}$ West of road $C$ .
Road $D$ is $1\text{ km}$ West of road $E$ .
Road $G$ is $1/2\text{ km}$ South of road $H$ .
Road $I$ is $1\text{ km}$ North of road $J$ .
Road $K$ is $1/2\text{ km}$ North of road $L$ .
Road $K$ is $1\text{ km}$ South of road $M$ .

If $K$ is parallel to $I$ , $K$ is $1/2\text{ km}$ South of $J$ and $1\text{ km}$ North of $G$ , then which of the following two roads would be $1/2\text{ km}$ apart?

Choose the correct answer: