NIMCET 2014 — Reasoning PYQ

Solution

Step 1: Define Present Ages

Let the present age of Rohit be $x$.

The problem states the father is "three times more" than Rohit. This means:

Step 2: Formulate the equation for 8 years later

After 8 years:

• Rohit's age $=x+8$

• Father's age $=4x+8$

According to the condition, the father will be two and a half ($2.5$ or $5/2$) times Rohit's age:

Step 3: Solve for $x$

Multiply both sides by 2:

• Present age of Rohit $=8\text{ years}$

• Present age of Father $=4\times 8=32\text{ years}$

Step 4: Calculate ages after a further 8 years

"After further 8 years" means a total of $8+8=16$ years from the present.

• Rohit's age after 16 years $=8+16=24\text{ years}$

• Father's age after 16 years $=32+16=48\text{ years}$

Step 5: Find the ratio

Conclusion:

After a further 8 years, the father will be 2 times Rohit's age.

Correct Option: 1 (2 times)