Solution:
To find limx→0f(x), we must check the Left Hand Limit (LHL) and the Right Hand Limit (RHL) at x=0.
1. Right Hand Limit (RHL):
As x→0+, x lies in the interval [0,1).
For 0 \leq x < 1, the greatest integer function [x]=0.
According to the function definition, when [x]=0, f(x)=0.
2. Left Hand Limit (LHL):
As x→0−, x lies in the interval [−1,0).
For -1 \leq x < 0, the greatest integer function [x]=−1.
Since [x]=0, we use the first part of the function: f(x)=[x]sin[x].
Substituting [x]=−1:
f(x)=−1sin(−1)=−1−sin(1)=sin(1)
Conclusion:
Since the Left Hand Limit and Right Hand Limit are not equal:
x→0−limf(x)=x→0+limf(x)
Therefore, limx→0f(x) does not exist.
Correct Option: 4