Solution
To solve this, we use the Stars and Bars method. However, the method typically requires variables to be non-negative (i.e., ≥0). We need to transform our given variables.
Step 1: Substitute the variables
Let:
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x1=x−1⟹x=x1+1
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y1=y−3⟹y=y1+3
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z1=z−4⟹z=z1+4
Now, since x≥1,y≥3,z≥4, our new variables are all non-negative:
x1,y1,z1≥0
Step 2: Rewrite the original equation
Substitute these into x+y+z=21:
(x1+1)+(y1+3)+(z1+4)=21
Step 3: Apply the Stars and Bars formula
The number of non-negative integral solutions for an equation of the form n1+n2+...+nr=n is given by:
Here, n=13 and r=3 (the number of variables x1,y1,z1).
Number of solutions=(3−113+3−1)
Number of solutions=(215)
Step 4: Calculate the final value
Correct Option: (B) 105