Explanation
Solution
1. Identify the vectors from the line equations
A line equation in the form ax−x1=by−y1=cz−z1 gives us a point on the line a and the direction vector b.
For Line 1:
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Point a1=(5,2,4)
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Direction b1=(1,2,−3)
For Line 2:
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Point a2=(−3,−5,1)
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Direction b2=(1,4,−5)
2. Find the difference between points (a2−a1)
a2−a1=(−3−5,−5−2,1−4)=(−8,−7,−3)
3. Calculate the cross product of direction vectors (b1×b2)
b1×b2=i^11amp;j^amp;2amp;4amp;k^amp;−3amp;−5
b1×b2=i^(−10−(−12))−j^(−5−(−3))+k^(4−2)
The magnitude ∣b1×b2∣=22+22+22=12=23.
4. Apply the Shortest Distance Formula
The formula for the shortest distance (d) between two skew lines is:
d=∣b1×b2∣(a2−a1)⋅(b1×b2)
Calculate the dot product:
(−8,−7,−3)⋅(2,2,2)=(−8×2)+(−7×2)+(−3×2)
Final Calculation:
To rationalize, multiply the top and bottom by 3:
Correct Option: (3) 63