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The absolute minimum value of the function f(x)=∣x2−x+1∣+[x2−x+1], where [t] denotes the greatest integer function, in the interval [−1,2], is:
Explanation
Solution:
Quadratic analysis: g(x)=x2−x+1 ki minimum value x=21 par 43 hoti hai.
Expression: f(x)=g(x)+[g(x)] kyunki g(x) > 0 hamesha rehta hai.
Minimum Value: f(21)=43+[43]=43+0=43.
Ans: (4)
Explanation
Solution:
Quadratic analysis: g(x)=x2−x+1 ki minimum value x=21 par 43 hoti hai.
Expression: f(x)=g(x)+[g(x)] kyunki g(x) > 0 hamesha rehta hai.
Minimum Value: f(21)=43+[43]=43+0=43.
Ans: (4)
