Let the line intersect the plane at the point . Let the point be the foot of perpendicular from the point on the line . If is the area of triangle , then is equal to:

180 Explanation: Solution 1. Point P nikaalna (Line aur Plane ka intersection): Line par kisi bhi general point ko maan sakte hain. Ise plane ki equation mein rakhein: Isliye, . 2. Point Q nikaalna (Foot of perpendicular from R on L): bhi line par hai, toh . Vector . Kyunki Line , toh unke direction ratios ka dot product zero hoga: Isliye, . 3. Triangle PQR ka Area ( ): Humein points mil gaye hain: , , aur . Area Answer:

How do I solve JEE 2023 Mathematics questions?

Practice JEE 2023 Mathematics previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

What is the difficulty level of JEE Mathematics questions?

JEE Mathematics questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Are JEE previous year papers available for free?

Yes. Mathem Solvex provides free access to JEE previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

JEE 2023 — Mathematics PYQ

JEE | Mathematics | 2023

Let the line $L: \frac{x-1}{2} = \frac{y+1}{-1} = \frac{z-3}{1}$ intersect the plane $2x + y + 3z = 16$ at the point $P$ . Let the point $Q$ be the foot of perpendicular from the point $R(1, -1, -3)$ on the line $L$ . If $\alpha$ is the area of triangle $PQR$ , then $\alpha^2$ is equal to:

Choose the correct answer: