JEE 2023 — Mathematics PYQ
JEE | Mathematics | 2023Let f1(x)=2x+33x+2,x∈R−{2−3} For n≥2, define fn(x)=f1(fn−1(x)) If f5(x)=bx+aax+b,gcd(a,b)=1, then a+b is equal to
Choose the correct answer:
- A.
3125
(Correct Answer) - B.
3025
- C.
3225
- D.
3325
3125
Explanation
Step 1: Matrix Form
f1(x)=2x+33x+2⟹M=(32amp;2amp;3)
Step 2: Finding M2
M2=(32amp;2amp;3)(32amp;2amp;3)=(1312amp;12amp;13)
Step 3: Finding M4
M4=M2⋅M2=(1312amp;12amp;13)(1312amp;12amp;13)=(313312amp;312amp;313)
Step 4: Finding M5
M5=M4⋅M=(313312amp;312amp;313)(32amp;2amp;3)=(15631562amp;1562amp;1563)
Step 5: Comparing with f5(x)=bx+aax+b
a=1563,b=1562
gcd(1563,1562)=1
Step 6: Final Value
a+b=1563+1562
a+b=3125
Explanation
Step 1: Matrix Form
f1(x)=2x+33x+2⟹M=(32amp;2amp;3)
Step 2: Finding M2
M2=(32amp;2amp;3)(32amp;2amp;3)=(1312amp;12amp;13)
Step 3: Finding M4
M4=M2⋅M2=(1312amp;12amp;13)(1312amp;12amp;13)=(313312amp;312amp;313)
Step 4: Finding M5
M5=M4⋅M=(313312amp;312amp;313)(32amp;2amp;3)=(15631562amp;1562amp;1563)
Step 5: Comparing with f5(x)=bx+aax+b
a=1563,b=1562
gcd(1563,1562)=1
Step 6: Final Value
a+b=1563+1562
a+b=3125

