For two non-zero complex numbers z1 and z2, if Re(z1z2)=0 and Re(z1+z2)=0, then which of the following are possible?
A. Im(z_1) > 0 and Im(z_2) > 0
B. Im(z_1) < 0 and Im(z_2) > 0
C. Im(z_1) > 0 and Im(z_2) < 0
D. Im(z_1) < 0 and Im(z_2) < 0
Explanation
Solution
Let z1=x1+iy1 and z2=x2+iy2.
Given Re(z1+z2)=0⟹x1+x2=0⟹x2=−x1.
Since z1,z2 are non-zero, let x1=a (where a=0). Then x2=−a.
Now, z1z2=(a+iy1)(−a+iy2)=(−a2−y1y2)+i(ay2−ay1).
Given Re(z1z2)=0:
Since a2 is always positive (as a=0), then −a2 must be negative.
This means y1 and y2 must have opposite signs.
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If y_1 > 0, then y_2 < 0 (Condition C)
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If y_1 < 0, then y_2 > 0 (Condition B)
Thus, B and C are the possible cases.
Correct Option: (3)
Explanation
Solution
Let z1=x1+iy1 and z2=x2+iy2.
Given Re(z1+z2)=0⟹x1+x2=0⟹x2=−x1.
Since z1,z2 are non-zero, let x1=a (where a=0). Then x2=−a.
Now, z1z2=(a+iy1)(−a+iy2)=(−a2−y1y2)+i(ay2−ay1).
Given Re(z1z2)=0:
Since a2 is always positive (as a=0), then −a2 must be negative.
This means y1 and y2 must have opposite signs.
-
If y_1 > 0, then y_2 < 0 (Condition C)
-
If y_1 < 0, then y_2 > 0 (Condition B)
Thus, B and C are the possible cases.
Correct Option: (3)