If m and n respectively are the numbers of positive and negative values of θ in the interval [−π,π] that satisfy the equation cos2θcos2θ=cos3θcos29θ, then mn is equal to
Explanation
Solving:
2cos2θcos2θ=2cos3θcos29θ
cos25θ+cos23θ=cos215θ+cos23θ
cos215θ−cos25θ=0⟹−2sin5θsin25θ=0
sin5θ=0⟹5θ=kπ⟹θ=0,±5π,±52π,±53π,±54π,±π
sin25θ=0⟹25θ=kπ⟹θ=0,±52π,±54π (already included)
Positive values (m): 5π,52π,53π,54π,π (Note: 0 is neither positive nor negative) ⟹m=5
Negative values (n): −5π,−52π,−53π,−54π,−π⟹n=5
mn=5×5=<strong>25
Answer :- 25
Explanation
Solving:
2cos2θcos2θ=2cos3θcos29θ
cos25θ+cos23θ=cos215θ+cos23θ
cos215θ−cos25θ=0⟹−2sin5θsin25θ=0
sin5θ=0⟹5θ=kπ⟹θ=0,±5π,±52π,±53π,±54π,±π
sin25θ=0⟹25θ=kπ⟹θ=0,±52π,±54π (already included)
Positive values (m): 5π,52π,53π,54π,π (Note: 0 is neither positive nor negative) ⟹m=5
Negative values (n): −5π,−52π,−53π,−54π,−π⟹n=5
mn=5×5=<strong>25
Answer :- 25