Explanation
Solution:
Given Information:
Key Properties used:
-
(X±Y)T=XT±YT
-
(XY)T=YTXT
-
(An)T=(AT)n
Step 1: Statement (S1) Check
Check if X=A13B26−B26A13 is symmetric (XT=X).
XT=(B26)T(A13)T−(A13)T(B26)T
Since (B26)T=(BT)26=(−B)26=B26 (as power is even) and (A13)T=A13:
Dhyan dein, yaha XT=−X aaya hai, iska matlab (S1) Skew-Symmetric hai, symmetric nahi. Isliye (S1) False hai.
Step 2: Statement (S2) Check
Check if Y=A26C13−C13A26 is symmetric.
YT=(C13)T(A26)T−(A26)T(C13)T
Since (C13)T=(CT)13=(−C)13=−C13 (as power is odd) and (A26)T=A26:
YT=(−C13)(A26)−(A26)(−C13)
Yaha YT=Y aaya hai, iska matlab (S2) Symmetric hai. Isliye (S2) True hai.
Conclusion:
-
(S1) is False
-
(S2) is True
Correct Option: (1) Only S2 is true