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The equation of the tangent to the hyperbola 9x2−4y2=1 parallel to the line 3x−2y+5=0 is:
Correct Answer: y=23x±265
Explanation
Solution
-
Hyperbola se values:
a2=9 aur b2=4.
-
Slope (m) nikaalein:
Line 3x−2y+5=0 ko y=mx+c ke roop mein likhne par:
Isliye, m=23.
-
Tangent ki equation ka formula:
Hyperbola ke liye tangent ki equation hoti hai: y=mx±a2m2−b2
y=23x±481−4=23x±481−16
Sahi jawab option (a) hai.
Explanation
Solution
-
Hyperbola se values:
a2=9 aur b2=4.
-
Slope (m) nikaalein:
Line 3x−2y+5=0 ko y=mx+c ke roop mein likhne par:
Isliye, m=23.
-
Tangent ki equation ka formula:
Hyperbola ke liye tangent ki equation hoti hai: y=mx±a2m2−b2
y=23x±481−4=23x±481−16
Sahi jawab option (a) hai.