JEE 2023 — Mathematics PYQ

Q: How do I solve JEE 2023 Mathematics questions?

Practice JEE 2023 Mathematics previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

Q: What is the difficulty level of JEE Mathematics questions?

JEE Mathematics questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Q: Are JEE previous year papers available for free?

Yes. Mathem Solvex provides free access to JEE previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

Question

JEE 2023 — Mathematics PYQ

JEE | Mathematics | 2023

Let $[\alpha]$ denote the greatest integer $\le \alpha$ . Then, $[\sqrt{1}] + [\sqrt{2}] + \dots + [\sqrt{120}]$ is equal to ______.

Choose the correct answer:

Explanation

Solution:

Hum values ko groups mein baantte hain jahaan square root ka integer part same rehta hai:

$1$ se $3$ tak ( $3$ values): $3 \times 1 = 3$
$4$ se $8$ tak ( $5$ values): $5 \times 2 = 10$
$9$ se $15$ tak ( $7$ values): $7 \times 3 = 21$
$16$ se $24$ tak ( $9$ values): $9 \times 4 = 36$
$25$ se $35$ tak ( $11$ values): $11 \times 5 = 55$
$36$ se $48$ tak ( $13$ values): $13 \times 6 = 78$
$49$ se $63$ tak ( $15$ values): $15 \times 7 = 105$
$64$ se $80$ tak ( $17$ values): $17 \times 8 = 136$
$81$ se $99$ tak ( $19$ values): $19 \times 9 = 171$
$100$ se $120$ tak ( $21$ values): $21 \times 10 = 210$

Total Sum $= 3 + 10 + 21 + 36 + 55 + 78 + 105 + 136 + 171 + 210 = \mathbf{825}$ .

Choose the correct answer:

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