Tip:A–D to answerE for explanationV for videoS to reveal answer
Let (α,β) be the centroid of the triangle formed by the lines 15x−y=82, 6x−5y=−4 and 9x+4y=17. Then, α+2β and 2α−β are the roots of the equation:
- A.
x2−13x+42=0
(Correct Answer) - B.
x2−10x+25=0
Correct Answer: x2−13x+42=0
Explanation
Solution:
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Step 1 (Vertices): Lines ko pair mein solve karke vertices nikaalein:
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(15x−y=82)∩(6x−5y=−4)⟹A(6,8)
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(6x−5y=−4)∩(9x+4y=17)⟹B(1,2)
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(15x−y=82)∩(9x+4y=17)⟹C(5,−7)
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Step 2 (Centroid): α=36+1+5=4 aur β=38+2−7=1.
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Step 3 (Roots):
r1=α+2β=4+2(1)=6
r2=2α−β=2(4)−1=7
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Step 4 (Equation): Roots 6 aur 7 wali equation:
x2−(6+7)x+(6×7)=0⟹x2−13x+42=0
Explanation
Solution:
-
Step 1 (Vertices): Lines ko pair mein solve karke vertices nikaalein:
-
(15x−y=82)∩(6x−5y=−4)⟹A(6,8)
-
(6x−5y=−4)∩(9x+4y=17)⟹B(1,2)
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(15x−y=82)∩(9x+4y=17)⟹C(5,−7)
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Step 2 (Centroid): α=36+1+5=4 aur β=38+2−7=1.
-
Step 3 (Roots):
r1=α+2β=4+2(1)=6
r2=2α−β=2(4)−1=7
-
Step 4 (Equation): Roots 6 aur 7 wali equation:
x2−(6+7)x+(6×7)=0⟹x2−13x+42=0