Step 1: Ellipse ki standard form
Di gayi equation hai:
Isse 36 se divide karne par:
Yahan a2=4 aur b2=9 hai.
Step 2: Chord PQ ki length nikalna
Maana chord PQ origin (0,0) se guzarti hai aur x-axis ke saath angle θ banati hai. Origin se ellipse par kisi point (rcosθ,rsinθ) ki doori r hai, toh:
Chunki PQ origin se dono taraf extend hoti hai, iski total length PQ=2r hogi.
(PQ/2)21=(PQ)24=4cos2θ+9sin2θ
(PQ)21=41(4cos2θ+9sin2θ)
Step 3: Chord RS ki length nikalna
Chunki RS chord PQ ke perpendicular hai, yeh x-axis ke saath (θ+90∘) ka angle banayegi.
Isliye, (RS)21 ke liye hum cosθ ko −sinθ aur sinθ ko cosθ se replace karenge:
(RS)21=41(4sin2θ+9cos2θ)
Step 4: Expression ki value calculate karna
Ab dono ko add karte hain:
(PQ)21+(RS)21=41[(4cos2θ+9sin2θ)+(4sin2θ+9cos2θ)]
Terms ko regroup karne par:
(PQ)21+(RS)21=41[4cos2θ+sin2θ+9sin2θ+cos2θ]
Chunki sin2θ+cos2θ=1 hota hai:
(PQ)21+(RS)21=41(41+91)
(PQ)21+(RS)21=41(369+4)=14413
Step 5: Final Comparison
Hame diya gaya hai ki yeh value qp ke barabar hai.
Yahan p=13 aur q=144 coprime hain.
Sahi Answer: (3) 157