Explanation
Step 1: Di gayi information
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Equation: cosA+2cosB+cosC=2
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Sides: a=3 (angle A ke opposite) aur c=7 (angle C ke opposite).
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Hame nikalna hai: cosA−cosC
Step 2: Trigonometric Identity ka upyog
Hum jante hain ki ek triangle mein A+B+C=π hota hai.
Di gayi equation ko rearrange karte hain:
Ab sum-to-product formula ka use karte hain:
2cos(2A+C)cos(2A−C)=2(2sin22B)
2cos(2π−B)cos(2A−C)=4sin22B
2sin2Bcos(2A−C)=4sin22B
sin(B/2) ko cancel karne par (kyunki sin(B/2)=0):
Dono taraf cos(B/2) se multiply karte hain:
cos(2A−C)cos(2B)=2sin2Bcos2B=sinB
cos(2A−C)sin(2A+C)=sinB
Step 3: Sine Rule ka upyog
Sine rule ke anusar: sinAa=sinBb=sinCc=2R
Iska matlab sinB=2Rb, sinA=2Ra aur sinC=2Rc.
Sawal ki conditions se hum nikal sakte hain ki:
b=23+7=5
Step 4: Cosine Formula se cosA aur cosC nikalna
Ab hamare paas teeno sides hain: a=3,b=5,c=7.
Step 5: Final Answer
cosA−cosC=1413+147=1420=710