JEE 2023 — Mathematics PYQ
JEE | Mathematics | 2023For α,β,γ,δ∈N, if ∫[(ex)2x+(xe)2x]lnxdx=α1(ex)βx−γ1(xe)δx+C, then α+2β+3γ−4δ is equal to:
Choose the correct answer:
- A.
4
(Correct Answer) - B.
-4
- C.
-8
- D.
1
4
Explanation
Solution:
Maan lijiye y=(ex)x. Dono side log lene par:
lny=xln(ex)=x(lnx−lne)=xlnx−x
Iska derivative lene par: y1dxdy=(x⋅x1+lnx)−1=lnx
Toh, dy=(ex)xlnxdx.
Integral ko likha ja sakta hai:
∫[(ex)2x+(x/e)2x1]lnxdx
y=(x/e)x rakhne par integral banta hai:
∫(y2+y−2)ydy=∫(y+y−3)dy=2y2+−2y−2+C
Maan wapas rakhne par:
=21(ex)2x−21(xe)2x+C
Compare karne par: α=2,β=2,γ=2,δ=2
Pucha gaya expression:
α+2β+3γ−4δ=2+2(2)+3(2)−4(2)=2+4+6−8=4
Answer: (1) 4
Explanation
Solution:
Maan lijiye y=(ex)x. Dono side log lene par:
lny=xln(ex)=x(lnx−lne)=xlnx−x
Iska derivative lene par: y1dxdy=(x⋅x1+lnx)−1=lnx
Toh, dy=(ex)xlnxdx.
Integral ko likha ja sakta hai:
∫[(ex)2x+(x/e)2x1]lnxdx
y=(x/e)x rakhne par integral banta hai:
∫(y2+y−2)ydy=∫(y+y−3)dy=2y2+−2y−2+C
Maan wapas rakhne par:
=21(ex)2x−21(xe)2x+C
Compare karne par: α=2,β=2,γ=2,δ=2
Pucha gaya expression:
α+2β+3γ−4δ=2+2(2)+3(2)−4(2)=2+4+6−8=4
Answer: (1) 4

