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JEE 2023 Mathematics PYQ — The number of ways of giving 20 distinct oranges to 3 children su… | Mathem Solvex | Mathem Solvex

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JEE 2023 — Mathematics PYQ

JEE | Mathematics | 2023

The number of ways of giving 20 distinct oranges to 3 children such that each child gets at least one orange is _____.

Choose the correct answer:

A.
3483838676
(Correct Answer)
B.
3483738576
C.
3883865576
D.
None

Correct Answer:

3483838676

Explanation

Number of ways = Total - (One child receive no orange + two child receive no orange)
= $3^{20} - (^{3} C_{1} (2^{20} - 2) +^{3} C_{2} 1^{20})$
= 3483838676

Explanation

Number of ways = Total - (One child receive no orange + two child receive no orange)
= $3^{20} - (^{3} C_{1} (2^{20} - 2) +^{3} C_{2} 1^{20})$
= 3483838676

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