JEE 2023 — Mathematics PYQ

$x^2-8x+15=2x-7$

take ${}^{\prime }{+}^{\prime }$

$\Rightarrow x^2-10x+22=0$

$x_1=5+\sqrt{3},x_2=5-\sqrt{3}$ (reject)

take ${}^{\prime }{-}^{\prime }$

$x^2-8x+15=7-2x$

$x^2-6x+8=0$

$x_3=4,x_4=2$ (reject)

Sum of roots = $5+\sqrt{3}+4=9+\sqrt{3}$