Let S={1,2,3,…,10}. Suppose M is the set of all subsets of S. Then the relation R={(A,B):A∩B=∅, A,B∈M} is:
Explanation
Given S={1,2,3,…,10}
Also, M=P(S) = power set of S
(i) Let A,B∈M
R={(A,B):A∩B=∅, A,B∈M} \hfill [Given]
If A=B⇒A∩B=∅
Hence, R is not reflexive.
(ii) As if (A,B)∈M⇒(B,A)∈M
So, R is symmetric.
(iii) Let (A,B)∈M and (B,C)∈M
⇒A∩B=∅ and B∩C=∅
But A∩C not necessarily empty
So, (A,C)∈/M
So, R is not transitive.
Explanation
Given S={1,2,3,…,10}
Also, M=P(S) = power set of S
(i) Let A,B∈M
R={(A,B):A∩B=∅, A,B∈M} \hfill [Given]
If A=B⇒A∩B=∅
Hence, R is not reflexive.
(ii) As if (A,B)∈M⇒(B,A)∈M
So, R is symmetric.
(iii) Let (A,B)∈M and (B,C)∈M
⇒A∩B=∅ and B∩C=∅
But A∩C not necessarily empty
So, (A,C)∈/M
So, R is not transitive.