JAMIA 2021 — Mathematics PYQ
JAMIA | Mathematics | 2021The solution of the differential equation dxdyex−y+x2e−z y is:
Choose the correct answer:
- A.
y=ex−y−x2 e−y+c
- B.
ey−ex=3x2+c $
ex−ey=3x3+c
Explanation
1. Given Differential Equation:
dxdy=ex−y+x2e−y
2. Simplify using the property of exponents (ea−b=ea⋅e−b):
dxdy=exe−y+x2e−y
3. Factor out e−y on the right side:
dxdy=e−y(ex+x2)
4. Separate the variables:
e−ydy=(ex+x2)dx
eydy=(ex+x2)dx
5. Integrate both sides:
∫eydy=∫(ex+x2)dx
6. Perform the integration:
ey=ex+3x3+C
Final Answer:
The solution is:
ey−ex=3x3+C
Explanation
1. Given Differential Equation:
dxdy=ex−y+x2e−y
2. Simplify using the property of exponents (ea−b=ea⋅e−b):
dxdy=exe−y+x2e−y
3. Factor out e−y on the right side:
dxdy=e−y(ex+x2)
4. Separate the variables:
e−ydy=(ex+x2)dx
eydy=(ex+x2)dx
5. Integrate both sides:
∫eydy=∫(ex+x2)dx
6. Perform the integration:
ey=ex+3x3+C
Final Answer:
The solution is:
ey−ex=3x3+C

