Explanation
Step 1: Write the determinant equation
Given:
1+x11amp;1amp;1+yamp;1amp;1amp;1amp;1+z=0
Step 2: Factor out x,y, and z
Since x,y,z=0, we can factor out x from the first row, y from the second row, and z from the third row:
xyzx1+1y1z1amp;x1amp;y1+1amp;z1amp;x1amp;y1amp;z1+1=0
Step 3: Apply row operations
Apply the row operation R1→R1+R2+R3:
xyz1+x1+y1+z1y1z1amp;1+x1+y1+z1amp;y1+1amp;z1amp;1+x1+y1+z1amp;y1amp;z1+1=0
Factor out the common term (1+x1+y1+z1) from the first row:
xyz(1+x1+y1+z1)1y1z1amp;1amp;y1+1amp;z1amp;1amp;y1amp;z1+1=0
Step 4: Simplify the remaining determinant
Apply column operations C2→C2−C1 and C3→C3−C1:
xyz(1+x1+y1+z1)1y1z1amp;0amp;1amp;0amp;0amp;0amp;1=0
The determinant of the identity matrix is 1:
Step 5: Solve for the expression
Since x,y,z=0, the product xyz=0. Therefore:
Rearranging the terms:
Using negative exponent notation: