JAMIA 2021 — Mathematics PYQJAMIA | Mathematics | 2021The value of tan3A−tan2A−tanA is equal toChoose the correct answer:A. tan3Atan2AtanA (Correct Answer)B. −tan3Atan2AtanAC. tanAtan2A−tan2Atan3A−tan3AtanACorrect Answer: tan3Atan2AtanAExplanationUsing the identity for tan(A+B): tan(3A)=tan(2A+A) tan(3A)=1−tan2AtanAtan2A+tanA tan3A(1−tan2AtanA)=tan2A+tanA tan3A−tan3Atan2AtanA=tan2A+tanA tan3A−tan2A−tanA=tan3Atan2AtanA Atan3Atan2AtanAB−tan3Atan2AtanACtanAtan2A−tan2Atan3A−tan3AtanADNone of theseShow Answer SExplanationUsing the identity for tan(A+B): tan(3A)=tan(2A+A) tan(3A)=1−tan2AtanAtan2A+tanA tan3A(1−tan2AtanA)=tan2A+tanA tan3A−tan3Atan2AtanA=tan2A+tanA tan3A−tan2A−tanA=tan3Atan2AtanA
