JAMIA 2023 β Mathematics PYQ
JAMIA | Mathematics | 2023(π΄∩π΅′)∪(π΄′∩π΅)∪(π΄′∩π΅′) ππ πππ’ππ π‘π
Choose the correct answer:
- A.
π΄∪π΅
- B.
π΄′∪π΅′
(Correct Answer) - C.
π΄′∩π΅′
- D.
π΄∪π΅′
π΄′∪π΅′
Explanation
Logic
The original expression is:
(Aβ©Bβ²)βͺ(Aβ²β©B)βͺ(Aβ²β©Bβ²)
1. Combine the terms containing Aβ²:
Using the distributive law on the last two parts:
(Aβ²β©B)βͺ(Aβ²β©Bβ²)=Aβ²β©(BβͺBβ²)
Since BβͺBβ² is the Universal Set (U), and Aβ²β©U=Aβ², the expression simplifies to:
(Aβ©Bβ²)βͺAβ²
2. Distribute Aβ² over (Aβ©Bβ²):
(AβͺAβ²)β©(Bβ²βͺAβ²)
Since AβͺAβ² is the Universal Set (U):
Uβ©(Bβ²βͺAβ²)
3. Final Result:
Aβ²βͺBβ²
Explanation
Logic
The original expression is:
(Aβ©Bβ²)βͺ(Aβ²β©B)βͺ(Aβ²β©Bβ²)
1. Combine the terms containing Aβ²:
Using the distributive law on the last two parts:
(Aβ²β©B)βͺ(Aβ²β©Bβ²)=Aβ²β©(BβͺBβ²)
Since BβͺBβ² is the Universal Set (U), and Aβ²β©U=Aβ², the expression simplifies to:
(Aβ©Bβ²)βͺAβ²
2. Distribute Aβ² over (Aβ©Bβ²):
(AβͺAβ²)β©(Bβ²βͺAβ²)
Since AβͺAβ² is the Universal Set (U):
Uβ©(Bβ²βͺAβ²)
3. Final Result:
Aβ²βͺBβ²

