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If π βΆ π
→ π
defined as of π(π₯) = x² + 1 then minimum value of π(π₯) is
- A.
4
- B.
3
- C.
2
- D.
1
(Correct Answer)
Explanation
-
Analyze the square term: For any real number x, the square of the number is always non-negative. Therefore:
-
Add the constant: Adding 1 to both sides of the inequality:
-
Determine the point of minimum: The smallest possible value for x2 is 0, which occurs when x=0. Substituting x=0 into the function:
Conclusion:
The minimum value of f(x) is 1.
Explanation
-
Analyze the square term: For any real number x, the square of the number is always non-negative. Therefore:
-
Add the constant: Adding 1 to both sides of the inequality:
-
Determine the point of minimum: The smallest possible value for x2 is 0, which occurs when x=0. Substituting x=0 into the function:
Conclusion:
The minimum value of f(x) is 1.