Explanation
Step 1: Logarithm ki Property apply karna
Humein pata hai ki log(A)+log(B)+log(C)=log(A⋅B⋅C). Is property ko sequence par lagane par:
S=log10(tan1∘⋅tan2∘⋅tan3∘…tan89∘)
Step 2: Trigonometric Identity ka use
Humein pata hai ki tan(90∘−θ)=cotθ. Iska matlab hai:
Saath hi, tanθ⋅cotθ=1 hota hai.
Step 3: Terms ko pair karna
Ab hum product ke andar terms ko pairs mein arrange karte hain:
(tan1∘⋅tan89∘)⋅(tan2∘⋅tan88∘)…(tan44∘⋅tan46∘)⋅tan45∘
Substitutions ke baad:
(tan1∘⋅cot1∘)⋅(tan2∘⋅cot2∘)…(tan44∘⋅cot44∘)⋅tan45∘
Humein pata hai ki har pair ka product 1 hoga aur tan45∘ ki value bhi 1 hoti hai.
Step 4: Final Calculation
Product simplify hokar 1 reh jayega:
Kyunki kisi bhi base par log(1) ki value 0 hoti hai:
Answer: Is expression ki value 0 hai.