CUET PG 2023 — Computer PYQ

\begin{aligned}
  & \text{Explanatlon:} \\
 & \text{Consider all the options} \\
 & \mathrm{Option~1:} \\
 & WX+W(X+y)+X(X+y)=X+Wy \\
 & \mathrm{WX}+\mathrm{WX}+\mathrm{WY}+\mathrm{XX}+\mathrm{XY}=\mathrm{X}+\mathrm{WY} \\
 & \mathrm{WX}+\mathrm{WY}+\mathrm{X}+\mathrm{X}\mathrm{Y}=\mathrm{X}+\mathrm{W}\mathrm{Y} \\
 & \mathrm{X}+\mathrm{W}\mathrm{y}=\mathrm{X}+\mathrm{W}\mathrm{y} \\
 & Option2 \\
 & \overline{w\bar{x}\left(y+\bar{z}\right)}+\bar{w}x=\bar{w}+x+\bar{y}z \\
 & \bar{w}+\overline{\bar{x}}+\bar{y}\overline{\bar{z}}+\bar{w}x=\bar{w}+x+\bar{y}z \\
 & \bar{w}+x+\bar{y}z+\bar{w}x=\bar{w}+x+\bar{y}z \\
 & \bar{w}+x+\bar{y}z=\bar{w}+x+\bar{y}z
\end{aligned}

Option 3:
$$(w\bar{x}(y+x\bar{z})+\bar{w}\bar{x}\bar{y})=x\bar{y}$$
$$(wx\bar{y}+wz+\bar{w}\bar{x}\bar{y})=x\bar{y}$$
$$(w\bar{x}y+w\bar{z}y+\bar{w}\bar{x}\bar{y})=x\bar{y}$$
$$(\bar{x}y+w\bar{z}y)=\bar{x}\bar{y}$$
$$\therefore (\bar{x}y+w\bar{z}y)\ne \bar{x}\bar{y}$$
Option 4:
$$(w+y)(wxy+wyz)=wxy+wyz$$
$$wxy+wyz+wxy+wyz=wxy+wyz$$
$$wxy+wyz=wxy+wy$$