JAMIA 2024 — Mathematics PYQ
JAMIA | Mathematics | 2024tan−1(21)+tan−1(31)=?
Choose the correct answer:
- A.
4π
(Correct Answer) - B.
2π
- C.
3π
4π
Explanation
Solution:
Hume iska maan (value) nikalna hai:
Step 1: Formula ka use karein
Hum jaante hain ki:
(Yahan xy < 1 hona chahiye. Is case mein \frac{1}{2} \times \frac{1}{3} = \frac{1}{6} < 1, isliye yeh formula valid hai.)
Step 2: Values ko formula mein rakhein
Yahan x=21 aur y=31 rakhne par:
Step 3: Numerator (ansh) aur Denominator (har) ko simplify karein
Numerator: 21+31=63+2=65
Denominator: 1−61=66−1=65
Ab in values ko wapas expression mein rakhte hain:
Step 4: Final value nikaalein
Hum jaante hain ki tan(4π)=1, isliye:
Final Answer:
tan−1(21)+tan−1(31) ki value hai:
Explanation
Solution:
Hume iska maan (value) nikalna hai:
Step 1: Formula ka use karein
Hum jaante hain ki:
(Yahan xy < 1 hona chahiye. Is case mein \frac{1}{2} \times \frac{1}{3} = \frac{1}{6} < 1, isliye yeh formula valid hai.)
Step 2: Values ko formula mein rakhein
Yahan x=21 aur y=31 rakhne par:
Step 3: Numerator (ansh) aur Denominator (har) ko simplify karein
Numerator: 21+31=63+2=65
Denominator: 1−61=66−1=65
Ab in values ko wapas expression mein rakhte hain:
Step 4: Final value nikaalein
Hum jaante hain ki tan(4π)=1, isliye:
Final Answer:
tan−1(21)+tan−1(31) ki value hai:

