JAMIA 2025 — Mathematics PYQ
JAMIA | Mathematics | 2025lim(x→0)xsinx is:
Choose the correct answer:
- A.
0
- B.
1
(Correct Answer) - C.
∞
- D.
Does not exist
1
Explanation
Mathematical Solution:
Given Equation :
x→0limxsinx
Jab hum x=0 rakhte hain, toh hamein 00 form milti hai, jo ki ek indeterminate form hai. Isse solve karne ke liye hum L'Hôpital's Rule ka upyog kar sakte hain:
x→0limxsinx=x→0limdxd(x)dxd(sinx)
Ab derivatives nikalne par:
x→0lim1cosx
Ab x=0 ki value rakhne par:
cos(0)=1
Final Answer:
x→0limxsinx=1
Explanation
Mathematical Solution:
Given Equation :
x→0limxsinx
Jab hum x=0 rakhte hain, toh hamein 00 form milti hai, jo ki ek indeterminate form hai. Isse solve karne ke liye hum L'Hôpital's Rule ka upyog kar sakte hain:
x→0limxsinx=x→0limdxd(x)dxd(sinx)
Ab derivatives nikalne par:
x→0lim1cosx
Ab x=0 ki value rakhne par:
cos(0)=1
Final Answer:
x→0limxsinx=1

