JAMIA 2025 Mathematics PYQ — Consider the following statements: S1: There exists infinite sets… | Mathem Solvex | Mathem Solvex
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JAMIA 2025 — Mathematics PYQ
JAMIA | Mathematics | 2025
Consider the following statements: S1: There exists infinite sets A, B, C such that A ∪ C = B ∪ C is finite. S2: There exists two irrational numbers x and y such that (x+y) is rational. Which of the following is true about S1 and S2?
Choose the correct answer:
A.
Only S1 is correct
B.
Only S2 is correct
C.
Both S1 and S2 are correct
(Correct Answer)
D.
None of S1 and S2 is correct
Correct Answer:
Both S1 and S2 are correct
Explanation
Statement S1 Analysis
S1: There exists infinite sets A,B,C such that A∪C=B∪C is finite.
To check if this is possible, let's look at the properties of the Union of sets.
If a set X is a subset of Y (i.e., X⊆Y), and Y is finite, then Xmust also be finite.
In the expression A∪C, both sets A and C are subsets of the result:
A⊆(A∪C)
C⊆(A∪C)
If A∪C is finite, then every subset of A∪C (including A and C) must be finite.
Therefore, it is mathematically impossible for A,B, or C to be infinite if their union is finite.
Conclusion for S1: Statement S1 is False.
Statement S2 Analysis
S2: There exists two irrational numbers x and y such that (x+y) is rational.
We can prove this by providing a simple counter-example (or "existence" example):
Let x=2 (which is irrational).
Let y=−2 (which is also irrational).
Now, let's calculate their sum:
x+y=2+(−2)
x+y=0
Since 0 is a rational number (it can be written as 0/1), the statement is true.
Another example:
Let x=3+5 and y=3−5. Both are irrational, but:
(3+5)+(3−5)=6
Since 6 is rational, the statement holds.
Conclusion for S2: Statement S2 is True.
Final Comparison
Statement
Status
Reason
S1
False
Union of infinite sets is always infinite.
S2
True
Irrational parts can cancel out during addition.
Final Answer:
S1 is False and S2 is True.
Explanation
Statement S1 Analysis
S1: There exists infinite sets A,B,C such that A∪C=B∪C is finite.
To check if this is possible, let's look at the properties of the Union of sets.
If a set X is a subset of Y (i.e., X⊆Y), and Y is finite, then Xmust also be finite.
In the expression A∪C, both sets A and C are subsets of the result:
A⊆(A∪C)
C⊆(A∪C)
If A∪C is finite, then every subset of A∪C (including A and C) must be finite.
Therefore, it is mathematically impossible for A,B, or C to be infinite if their union is finite.
Conclusion for S1: Statement S1 is False.
Statement S2 Analysis
S2: There exists two irrational numbers x and y such that (x+y) is rational.
We can prove this by providing a simple counter-example (or "existence" example):
Let x=2 (which is irrational).
Let y=−2 (which is also irrational).
Now, let's calculate their sum:
x+y=2+(−2)
x+y=0
Since 0 is a rational number (it can be written as 0/1), the statement is true.