NIMCET 2016 — Mathematics PYQ

Q: How do I solve NIMCET 2016 Mathematics questions?

Practice NIMCET 2016 Mathematics previous year questions with step-by-step solutions on Mathem Solvex. Each question includes a detailed explanation and video solution to help you master the concept quickly.

Q: What is the difficulty level of NIMCET Mathematics questions?

NIMCET Mathematics questions range from moderate to advanced difficulty. Consistent practice with official previous year papers and topic-wise drills on Mathem Solvex is the most effective preparation strategy.

Q: Are NIMCET previous year papers available for free?

Yes. Mathem Solvex provides free access to NIMCET previous year question papers and topic-wise PDFs. You can download them or attempt them as timed live mock tests directly on the platform.

Question

NIMCET 2016 — Mathematics PYQ

NIMCET | Mathematics | 2016

The probability that A speaks truth is 4 / 5 while this probability for B is 3 / 4. The probability that they contradict each other when asked to speak on a fact is

Choose the correct answer:

Explanation

Concept:

$P (A^{'}) = 1 - P (A)$

Calculations:

Given, A : the event A speaks truth
⇒ P(A) = $\frac{4}{5}$

A' : the event A does not speak truth
⇒ P(A') = 1 - P(A) = 1 - $\frac{4}{5}$ = $\frac{1}{5}$

B : the event B speaks truth
⇒ P(B) = $\frac{3}{4}$

B' : the event B does not speak truth
⇒ P(B') = 1 - P(B) = 1 - $\frac{3}{4}$ = $\frac{1}{4}$

The probability that they contradict each other when asked to speak on a fact = P(A)P(B') + P(B)P(A')
= $\frac{4}{5} \times \frac{1}{4} + \frac{3}{4} \times \frac{1}{5}$
= $\frac{7}{20}$