Tip:A–D to answerE for explanationV for videoS to reveal answer
Consider the equation (40)x=(132)y in some bases x and y. Then a possible set of values of x and y are
- A.
8 and 12
(Correct Answer) - B.
12 and 8
- C.
6 and 12
- D.
12 and 6
Explanation
Concept:
(ABCD)a=D∗a0+C∗a1+B∗a2+A∗a3
Calculation:
(40)x=(132)y
⇒ 0 × x0 + 4 × x1 = 2 × y0 + 3 × y1 + 1 × y2
⇒ 4x=2+3y+y2
⇒ 4x−2=3y+y2
All options are wrong
Explanation
Concept:
(ABCD)a=D∗a0+C∗a1+B∗a2+A∗a3
Calculation:
(40)x=(132)y
⇒ 0 × x0 + 4 × x1 = 2 × y0 + 3 × y1 + 1 × y2
⇒ 4x=2+3y+y2
⇒ 4x−2=3y+y2
All options are wrong