Differentiate {-log (log x), x > 1} with respect to x
Explanation
Concept:
Chain rule: dxd[f(g(x))]=f′(g(x))g′(x)
Calculation:
Here, -log (log x), x > 1
Let, log x = y
Differentiating with respect to x, we get
⇒dxdy=x1 ... (1)
Now, -log (log x) = -log y
dxd(−logy)=−y1dxdy
=−xlogx1 ... (from (1))
Explanation
Concept:
Chain rule: dxd[f(g(x))]=f′(g(x))g′(x)
Calculation:
Here, -log (log x), x > 1
Let, log x = y
Differentiating with respect to x, we get
⇒dxdy=x1 ... (1)
Now, -log (log x) = -log y
dxd(−logy)=−y1dxdy
=−xlogx1 ... (from (1))