What is the largest area of an isosceles tringle with two edges of length 3 ?
Explanation
Concept:
Area of isosceles triangle =1/2× l × l × sin θ where, θ is vertex angle of the isosceles triangle.
Calculation:
Here length = 3
The area is given by 1/2× 3×3×sin θ where θ is the vertex angle of the isosceles triangle.
Here, we required maximum area so θ = 90
∴ Area =1/2× 9 = 9/2
Hence, option (4) is correct.
Explanation
Concept:
Area of isosceles triangle =1/2× l × l × sin θ where, θ is vertex angle of the isosceles triangle.
Calculation:
Here length = 3
The area is given by 1/2× 3×3×sin θ where θ is the vertex angle of the isosceles triangle.
Here, we required maximum area so θ = 90
∴ Area =1/2× 9 = 9/2
Hence, option (4) is correct.
