The equation of the hyperbola with center at the origin, length of the transverse axis is 6 and one focus at (0, 4) is?
Explanation
Concept:
The equation of the hyperbola is b2y2−a2x2=1 with the foci (0,±c)
Length of the transverse axis = 2a
Calculations:
Since the coordinates of the one focus at (0,4)=(0,±c), it is a case of vertical hyperbola
⇒c=2
It is a case of vertical hyperbola
⇒The equation of hyperbola is b2y2−a2x2=1 ... (1)
<br>⇒Length of the transverse axis =6
⇒2a=6
<br>⇒a=3
⇒c2=a2+b2
<br>⇒22=32+b2
⇒b2=7
<br>⇒Equation (1) becomes
⇒9y2−7x2=1
<br>⇒Hence, The equation of the hyperbola with center at the origin, length of the transverse axis is 6 and one focus at (0, 4) is 9y2−7x2=1
Explanation
Concept:
The equation of the hyperbola is b2y2−a2x2=1 with the foci (0,±c)
Length of the transverse axis = 2a
Calculations:
Since the coordinates of the one focus at (0,4)=(0,±c), it is a case of vertical hyperbola
⇒c=2
It is a case of vertical hyperbola
⇒The equation of hyperbola is b2y2−a2x2=1 ... (1)
<br>⇒Length of the transverse axis =6
⇒2a=6
<br>⇒a=3
⇒c2=a2+b2
<br>⇒22=32+b2
⇒b2=7
<br>⇒Equation (1) becomes
⇒9y2−7x2=1
<br>⇒Hence, The equation of the hyperbola with center at the origin, length of the transverse axis is 6 and one focus at (0, 4) is 9y2−7x2=1