The direction cosines of the vector a=(−2i^+j^−5k^) are?
Explanation
Concept:
The direction cosines of the vector are the corresponding coordinates of the vector divided by the length (magnitude) of the vector.
Calculation:
Here, a=(−2i^+j^−5k^)
∣a∣=(−2)2+12+(−5)2=30
The direction cosines of the given vector are
30−2,301,30−5
Hence, option (3) is correct.
Explanation
Concept:
The direction cosines of the vector are the corresponding coordinates of the vector divided by the length (magnitude) of the vector.
Calculation:
Here, a=(−2i^+j^−5k^)
∣a∣=(−2)2+12+(−5)2=30
The direction cosines of the given vector are
30−2,301,30−5
Hence, option (3) is correct.