Differential coefficient of log10x with respect to logx10 is
Explanation
**Concept:**
logax=logalogx
dxd(x1)=x2−1
Calculation:
Let y=log10x and z=logx10
We have to find the value of dzdy
yz=log10logx⋅logxlog10=1
⇒y=z1
⇒dzdy=−z21=−y2=−(log10x)2
=−(log10)2(logx)2
Hence, option (1) is correct.
Explanation
**Concept:**
logax=logalogx
dxd(x1)=x2−1
Calculation:
Let y=log10x and z=logx10
We have to find the value of dzdy
yz=log10logx⋅logxlog10=1
⇒y=z1
⇒dzdy=−z21=−y2=−(log10x)2
=−(log10)2(logx)2
Hence, option (1) is correct.